427518domain: NAppears in sequencesNumbers n such that the average of prime(n) and prime(n+1) is a perfect cube.at n=24A076693a(n) = Sum_{k=1..n} binomial(n,k) * d(k), where d(k) = the number of positive divisors of k.at n=16A160399a(n) = 3*binomial(n+1, 5).at n=28A253942