39647713

Appears in sequences

• Numbers k such that k | 4^k + 2^k + 1.at n=17A057845
• a(n) = the denominator of b(n): {b(n)} is such that the continued fraction (of rational terms) [b(1);b(2),...,b(n)] equals the F(n+1)^2/F(n)^2, for every positive integer n, where F(n) is the n-th Fibonacci number.at n=6A128273