37025

Appears in sequences

• a(n) = n^3 + n^2 - 1.at n=32A003777
• Least j > 1 for n > 0 such that j^2 = (n^2 + 1)*(k^2) + (n^2 + 1)*k + 1 where k sequence = A106230.at n=33A106229
• a(n) = 34*n^2 - 1.at n=32A158588
• Least number k > 0 such that 2^k begins with exactly n consecutive decreasing digits.at n=4A244848
• Numbers m such that 4^(m-1) == 1 (mod (m-1)^2 + 1).at n=9A273870