36513

Appears in sequences

• Days per century for British calendar from first century, following Gregorian calendar after A.D. 1752.at n=17A011770
• a(n) = s(1)t(n) + s(2)t(n-1) + ... + s(k)t(n-k+1), where k = [ n/2 ], s = (Lucas numbers), t = (composite numbers).at n=25A025091
• Sequence coincides with union of its first and 2nd binomial transforms, ordered by size, with a(0)=1.at n=20A090859
• Numbers k such that k and k^2 use only the digits 1, 3, 5, 6 and 9.at n=25A137035
• Number of increasing sequences of n integers x(1),...,x(n) with values in 1..5*n such that x(j) divides x(k) iff j divides k.at n=18A180382