3637383940

Appears in sequences

• Partition the concatenation 1234567...of natural numbers into successive strings which are multiples of 5, all different and > 5. (0 never taken as the most significant digit.)at n=7A077298
• Concatenation of the terms gives natural numbers in sequence such that N-th partial concatenation is a multiple of n.at n=9A109855
• Concatenate the consecutive increasing numbers starting with Harshad(n) and ending with Harshad(n+1).at n=17A112131