3524489

Appears in sequences

• Convolution of natural numbers n >= 1 with Fibonacci numbers F(k), k >= 3.at n=26A033937
• a(n) = (Fibonacci(2n+1) + Fibonacci(2n+2)*phi)/kappa(phi/Fibonacci(4n+2)) where kappa(x) is the sum of successive remainders by computing the Euclidean algorithm for (1,x).at n=5A088914
• a(n) = Fibonacci(3*n) - (2 + (-1)^n)*Fibonacci(n).at n=10A273623