3478608domain: NAppears in sequencesa(n) is the number of preference profiles in the stable marriage problem with 4 men and 4 women that generate n possible stable matchings.at n=5A344667Numbers k such that k*A003557(A003961(k)) divides A353790(k), where A353790(n) = phi(A003973(n)) * A064989(A003973(n)).at n=38A353797