331362185domain: NAppears in sequencesa(0)=1; thereafter a(n+1)=F(n+3)*a(n)+F(n+3) where F_n is Fibonacci's sequence 0,1,1,2,3,5,8, etc.at n=8A147690a(n) is the least k such that the average number of infinitary divisors of {1..k} is >= n.at n=14A344274