313671601domain: NAppears in sequencesQuotient Fibonacci(5*n)/(5*Fibonacci(n)), where Fibonacci(n) = A000045(n).at n=10A088545a(n) = F(n-th squarefree)/product{p=primes,p|(n-th squarefree)} F(p), where F(m) is m-th Fibonacci number.at n=33A115022