30481920domain: NAppears in sequencesa(n) = n! * binomial(n,3).at n=6A001805Let M_n be the n X n matrix with M_n(i,j)=1/(i+j+4); then a(n)=1/det(M_n).at n=2A069643Numbers whose divisors have a mean abundancy index that is larger than 3.at n=14A374779