30392377

Appears in sequences

• Define G(x) = Sum_{n>=0} a(n)*x^n/2^[n*(n-1) - A000120(n)], then [x^n] G(x)^(1/2^n) = 1 for n>=0, where A000120(n) = number of 1's in binary expansion of n.at n=5A134096