295272domain: NAppears in sequencesRatios of consecutive terms approach Pi alternating from below and above.at n=11A214839E.g.f.: 1 / (1 + x^2/2 + log(1 - x)).at n=8A337060a(n) = floor((2*n - 3 + sqrt(1 + 4*n!))/2).at n=13A372265a(n) = Sum_{k=0..n} 3^(n-k) * binomial(n,k) * binomial(4*n+1,k).at n=5A388135