290023

Properties

Appears in sequences

• Josephus problem: numbers m such that, when m people are arranged on a circle and numbered 1 through m, the final survivor when we remove every 4th person is one of the first three people.at n=38A005427
• a(1) = 1 and a(n) = ceiling((Sum_{k=1..n-1} a(k))/3) for n >= 2.at n=46A072493
• Primes p such that the differences between the 5 consecutive primes starting with p are (4,6,6,2).at n=22A078956
• Prime numbersat n=25227