28143753122domain: NAppears in sequencesa(n) = F(2n+1) + F(2n-1) - 1.at n=25A005592a(n) = 5*F(n)^2 + 3*(-1)^n where F(n) are the Fibonacci numbers A000045.at n=25A047946Partial sums of A215602.at n=24A215580a(n) = Lucas(2*n) + 2*(-1)^n + 1.at n=24A366508