275938domain: NAppears in sequencesa(n) is the least k such that f(a(n-1)+1) + ... + f(k) > f(a(n-2)+1) + ... + f(a(n-1)) for n > 1, where f(n) = 1/(n+5) and a(1) = 1.at n=10A225920a(n) = Sum_{k=0..n} 3^(n-k) * floor(k/3).at n=14A368344