27503832domain: NAppears in sequencesa(n) = H(n)*n!/(floor(n/2))!, where H(n) = Sum_{k=1..n} 1/k, the n-th harmonic number.at n=13A124078a(n) = H(2n+1)*(2n+1)!/n!, where H(n) = Sum_{k=1..n} 1/k, the n-th harmonic number.at n=6A124079