269253

Appears in sequences

• a(n) = floor(Fibonacci(n)/5).at n=31A004698
• Maximum element in the continued fraction expansion of F(n+1)^5/F(n)^5 where F=A000045.at n=14A113506
• a(n) = floor(L^3*{phi^(3*n-2), phi^(3*n-1), phi^(3*n-2) + phi^(3*n-1)}) where L = (1 + sqrt(5))/(2*sqrt(5)) and phi = (1 + sqrt(5))/2.at n=27A115315
• Maximum value of the cyclic convolution of first n primes with themselves.at n=38A299111