25769279491domain: NAppears in sequencesNumerator of I(n) = Integral_{x=0..1/(4^n)} (1-sqrt(x))^2 dx; e.g., I(3) = 323/24576. The denominator is b(n) = 96*16^(n-1); e.g., b(3) = 24576.at n=16A092841