25451905333domain: NAppears in sequencesa(n) = numerator(b(n)), where b(1) = b(2) = 1, b(n) = (b(n-1) + b(n-2))/(n-1).at n=23A069943a(n) = denominator of 1/(1 + 1/(1 + 2/(1 + ... (1 + n)))).at n=21A289491a(n) = A000085(4*n+3)/2^(n+2).at n=5A316333