2537720635domain: NAppears in sequencesPartial sums of squares of Lucas numbers.at n=21A005970a(n) = Lucas(4n+1) - 1, or 5*Fibonacci(2n)*Fibonacci(2n+1).at n=11A081017a(n) = Lucas(3*n) - 1.at n=15A100233Continued fraction expansion for exp( Sum_{n>=1} 1/(n*A014448(n)) ), where A014448(n) = (2+sqrt(5))^n + (2-sqrt(5))^n.at n=22A174506