2510489domain: NAppears in sequencesNumerators of continued fraction convergents to sqrt(365).at n=8A041690a(n) = 19*a(n-1) + a(n-2), starting with a(0) = 2 and a(1) = 19.at n=5A090308a(n) = n^5 + 5*n^3 + 5*n.at n=19A261391