2477475domain: NAppears in sequencesa(1) = 3 = 1*3; a(n) = smallest multiple of a(n-1) which is a product of two consecutive odd numbers.at n=4A068858Numbers with exactly 5 distinct odd prime divisors {3,5,7,11,13}.at n=31A147578a(n) = n*(n + 1)*(n + 2)*(n + 3)*(n^2 - n + 5)/120.at n=24A256860