24563311309domain: NAppears in sequencesa(n) = prime(2^n).at n=30A033844Numbers that begin a run of consecutive integers k such that PrimePi(k) divides 2^k.at n=29A073799a(n) = prime(4^n).at n=15A119772(8^n)-th prime.at n=10A119773(32^n)-th prime.at n=6A11977864^n-th prime.at n=5A119779