23909723domain: NAppears in sequencesa(n) = reduced numerator of Sum_{p <= n} Sum_{k=1..floor(log(n)/log(p))} 1/p^k, where p runs over the primes.at n=17A294208a(n) = reduced numerator of Sum_{p <= n} Sum_{k=1..floor(log(n)/log(p))} 1/p^k, where p runs over the primes.at n=18A294208