2358343

Appears in sequences

• 6-white numbers: partition digits of n^6 into blocks of 6 starting at right; sum of these 6-digit numbers equals n.at n=20A274833
• a(n) = a(n-1) + 3*a(n-2) -2*a(n-3) - 2*a(n-4), where a(0) = 1, a(1) = 3, a(2) = 5, a(3) = 7.at n=29A295717