2228174domain: NAppears in sequencesLet b(n,0) = n and b(n,k) = 2*b(n,k-1) + 1 for k > 0. Then a(n) = b(n,1) + b(n,2) + ... + b(n,n).at n=15A190730Smallest positive integer m such that m, m+1, m+2, m+3 are divisible by 2n+1, 2n+3, 2n+5, 2n+7 respectively.at n=21A279259a(n) = 68*2^n - 50 (n>=1).at n=14A304518