214956

Appears in sequences

• Number of length n binary words that contain 000 and 001 and 010 and 011 and 100 and 101 and 110 and 111 as contiguous subsequences. The 3 letter subsequences are allowed to overlap.at n=9A242167
• a(n) = 324*n^2 - 804*n + 468 (n>=2).at n=25A304619
• a(n) = numerator of -(1/4)*n!*(2 + n!)*(-2 + 1/(1 + floor(n/2 - 1/2))) - n!*Sum_{m=1..1 + 2*floor(n/2 - 1/2)} 1/m.at n=5A368592