21403533312domain: NAppears in sequencesa(0) = 1; a(n) = LCM(n, sum{k=0 to n-1}[a(k)]).at n=18A057827a(1) = 1, a(2) = (2*1)/1 = 2. a(n+1) = (n+1)*a(n) divided by the largest prime divisor of a(n).at n=27A100773