208116domain: NAppears in sequencesNumbers n such that the sum of the digits of Sum_{k=1..n} (k!) is divisible by n.at n=27A109657Triangle T(n,k) read by rows with T(n,0) = (2*n)! / (2^n * n!) for n >= 0 and T(n,k) = (Sum_{i=k..n} binomial(i-1,k-1) * 2^i * i! / (2*i)!) * (2*n)! / (2^n * n!) for 0 < k <= n.at n=39A350557