196612

Appears in sequences

• Bode numbers multiplied by 10: 4 + 3*floor(2^(n-1)).at n=17A003461
• Maximal term in Collatz-iteration started at 2^n+1.at n=16A087970
• a(n) = 6*2^n + 4 (Bode Number A003461(n+2)) except for a(1)=6.at n=14A091307
• 1/4 the number of (n+1) X 5 0..2 arrays with every 2 X 2 subblock having distinct clockwise edge differences.at n=33A209723
• Number of length n+2 0..3 arrays with every three consecutive terms having the sum of some two elements equal to twice the third.at n=42A248428