190982

Appears in sequences

• Backward iterated ( limited ) Fibonacci approximation: A000045.at n=23A116557
• a(1) = 1, then a(n) is the least integer > a(n-1) such that n is the maximum element in the continued fraction for 1/a(1) + 1/a(2) + ... + 1/a(n).at n=34A174604