180583

Appears in sequences

• Numbers k such that the period of the continued fraction for sqrt(k) contains exactly 71 ones.at n=23A031839
• a(n) = a(n-1) + a(n-2) + 2 a([n/2]), where a(0) = 1, a(1) = 1, a(2) = 1.at n=23A298346