180127domain: NAppears in sequencesa(1) = 1, then a(n) is the least integer > a(n-1) such that n is the maximum element in the continued fraction for 1/a(1) + 1/a(2) + ... + 1/a(n).at n=33A174604a(n) = Fibonacci(2n-1) - 2^n + binomial(n,2) + 2.at n=14A356696