180034

Appears in sequences

• Sum of a(n) terms of 1/k^(6/7) first exceeds n.at n=33A056183
• a(n) = a(n-1) + 3*a(n-2) -2*a(n-3) - 2*a(n-4), where a(0) = 0, a(1) = 0, a(2) = -1, a(3) = 1.at n=28A295725