177198domain: NAppears in sequencesMatrix cube of triangle U = A136228, read by rows.at n=23A136236a(0)=1; thereafter a(n+1)=F(n+3)*a(n)+F(n+3) where F_n is Fibonacci's sequence 0,1,1,2,3,5,8, etc.at n=6A147690E.g.f. satisfies A(x) = ( 1 - log(1 - x*A(x))/A(x) )^3.at n=6A377359