17252515280domain: NAppears in sequencesa(n) = denominator of sum{k=1 to n} 1/A127515(k).at n=24A127517a(n) = denominator of sum{k=1 to n} 1/A127515(k).at n=25A127517a(n) = denominator of sum{k=1 to n} 1/A127515(k).at n=26A127517a(n) = denominator of sum{k=1 to n} 1/A127515(k).at n=27A127517