159845400domain: NAppears in sequencesLet b(0)=0. For n >= 1, b(n) is the least k > b(n-1)+1 such that k divides (k-1)!/b(n-1)!, and a(n) = (b(n)-1)!/(b(n-1)!*b(n)).at n=4A079759a(n) = A092914(n)/n = the least integer value of (n-1)!/(n*k!).at n=22A092916Duplicate of A079759.at n=4A109894a(n) = A332560(n)/A332559(n).at n=20A332561