158117071612domain: NAppears in sequencesLesser of a pair of records in A066272.at n=17A093071a(n) = ((2*n-1)!! + (-1)^((n-1)*(n-2)/2))/2.at n=11A220092(A001147(n+1)-1)/2, equals the index of A249348(n) within the triangular numbers A000217.at n=11A249349