1567641600

Appears in sequences

• Dwork-Kontsevich sequence evaluated at 2*n.at n=8A007757
• a(n) = gcd(n!, n!*(1 + 1/2 + 1/3 + ... + 1/n)).at n=17A056612
• a(n) = gcd(n!, n!*(1 + 1/2 + 1/3 + ... + 1/n)).at n=18A056612
• Cumulative product of triple factorial A007661.at n=9A114778
• For n >= 1, put A_n(z) = Sum_{j>=0} (n*j)!/(j!^n) * z^j and B_n(z) = Sum_{j>=0} (n*j)!/(j!^n) * z^j * (Sum_{k=1..j*n} (1/k)), and let b(n) be the largest integer for which exp(B_n(z)/(b(n)*A_n(z))) has integral coefficients. The sequence is b(n).at n=17A131657
• For n >= 1, put A_n(z) = Sum_{j>=0} (n*j)!/(j!^n) * z^j and B_n(z) = Sum_{j>=0} (n*j)!/(j!^n) * z^j * (Sum_{k=1..j*n} (1/k)), and let b(n) be the largest integer for which exp(B_n(z)/(b(n)*A_n(z))) has integral coefficients. The sequence is b(n).at n=18A131657
• For n >= 1, put A_n(z) = Sum_{j>=0} (n*j)!/(j!^n) * z^j and B_n(z) = Sum_{j>=0} (n*j)!/(j!^n) * z^j * (Sum__{k=j+1..j*n} (1/k)), and let u(n) be the largest integer for which exp(B_n(z)/(u(n)*A_n(z))) has integral coefficients. The sequence is u(n).at n=17A131658
• For n >= 1, put A_n(z) = Sum_{j>=0} (n*j)!/(j!^n) * z^j and B_n(z) = Sum_{j>=0} (n*j)!/(j!^n) * z^j * (Sum__{k=j+1..j*n} (1/k)), and let u(n) be the largest integer for which exp(B_n(z)/(u(n)*A_n(z))) has integral coefficients. The sequence is u(n).at n=18A131658
• a(n) = Product_{k=0..n} (3*k)!.at n=3A268504
• a(n) = Product_{k=0..n} (k*n)!.at n=3A272096
• Product of products of parts over all strict integer partitions of n.at n=9A325504