15219319500domain: NAppears in sequencesa(n) = Product_{j=0..floor(n/2)} binomial(n,j).at n=10A061778a(n) = n^1*(n+1)^2*(n+2)^3*(n+3)^4*(n+4)^5/(1!*2!*3!*4!*5!).at n=6A120408a(n) = Product_{i=floor((n + 1)/2)..n-1} binomial(n-1, i).at n=11A208653