1339484197domain: NAppears in sequencesa(n) = prime(2^n).at n=26A033844Numbers that begin a run of consecutive integers k such that PrimePi(k) divides 2^k.at n=25A073799a(n) = prime(4^prime(n)).at n=5A096325a(n) = prime(4^n).at n=13A119772