131767domain: NAppears in sequencesNumerators of continued fraction convergents to sqrt(365).at n=5A041690a(n) = 4*n^4 + 8*n^3 - 4*n - 1 = (2*n^2 - 1)*(2*n^2 + 4*n + 1).at n=13A057769a(n) = 19*a(n-1) + a(n-2), starting with a(0) = 2 and a(1) = 19.at n=4A090308