13029390domain: NAppears in sequencesA Fibonacci convolution.at n=18A099483a(n) = ceiling(Fibonacci(n)/3).at n=38A293543a(n) = round(Fibonacci(n)/3).at n=38A293544Upper (1/3)-midsequence of (F(2n)) and (F(2n+1)), where F=A000045 (Fibonacci numbers); see Comments.at n=18A387783