130022

Appears in sequences

• a(n) = a(n-1) + a(n - 1 minus the number of terms of a(k) == (mod 6) so far).at n=36A060733
• Numbers k such that d(k) < d(k+1) < d(k+2) < d(k+3) < d(k+4), where d(n) is the number of divisors of n.at n=22A364717