124161domain: NAppears in sequencesa(1) = 1, then a(n) is the least integer > a(n-1) such that n is the maximum element in the continued fraction for 1/a(1) + 1/a(2) + ... + 1/a(n).at n=27A174604a(n) = Sum_{k=1..n} (-2)^(n - floor(n/k)).at n=14A345109