123448657904
domain: N
Appears in sequences
- Given g.f. A(x), the even bisections of both A(x) and A(x)^2 are equal, and the odd bisections of both A(x)^2 and A(x)^3 are equal (after the initial terms).at n=21A351771
- G.f. A(x) satisfies: A(x) = (1 + 2*x*A(x)^3)^2 / (1 + x*A(x)^3).at n=10A352383
- G.f. (1/x)*Series_Reversion( x*(1-x)*(3 - 2*x + sqrt(1+4*x-4*x^2))/4 ).at n=20A352701