122167958641domain: NAppears in sequencesBase-4 digits are, in order, the first n terms of the periodic sequence with initial period 1,3,0.at n=18A037597a(n) = a(n-1) + 2^(A047258(n)) for n>1, a(1)=1.at n=18A113867a(n) = (2^(3*n + 3 + (-1)^n) - (6 + (-1)^n))/9, for n >= 1.at n=11A350053a(n) = (4^(3*n+2) - 7)/9.at n=5A350054