115315200

Appears in sequences

• a(n) = n!*2^(n-1)/Product_{k=1..n} tau(k) where tau = A000005.at n=12A074740
• a(n) = ((6n-5)!!!+(6n-4)!!!)/(6n-3).at n=4A274117
• Numbers k achieving record abundance (sigma(k) > 2*k) via a residue-based measure M(k) (see Comments), analogous to superabundant numbers A004394.at n=35A362081