1119744
domain: N
Appears in sequences
- Mean integral divisors associated with A048751.at n=12A048752
- For an integer k with prime factorization p_1*p_2*p_3* ... *p_m let k* = (p_1+1)*(p_2+1)*(p_3+1)* ... *(p_m+1) (A064478); sequence gives k such that k* is divisible by k.at n=28A064476
- Third column of triangle A067410 and second column of A067417.at n=8A067411
- Triangle with columns built from certain power sequences.at n=46A067417
- For n>3, a(n) = smallest number divisible by exactly n-2 previous terms; a(n)=n for n<=3.at n=31A084391
- a(n) = n^3*3^(n-1).at n=8A086603
- Number of divisors of n! that are coprime to n.at n=38A095997
- Triangle read by rows: T(n,k) = 2^n * 3^k, 0 <= k <= n, n >= 0.at n=52A100851
- a(n) = ceiling(6^n/n).at n=8A129790
- a(n) = floor(6^n/n).at n=8A129796
- a(n) = 6*a(n-2) for n > 2; a(1) = 1, a(2) = 4.at n=15A164532
- a(n) = 6*a(n-2) for n > 2; a(1) = 4, a(2) = 1.at n=14A166027
- a(n) = floor(sqrt(n)) * a(n-1), starting with 1.at n=16A195458
- Number of (n+1)X8 0..2 arrays with no 2X2 subblock having equal diagonal elements or equal antidiagonal elements, and new values 0..2 introduced in row major order.at n=1A203983
- T(n,k)=Number of (n+1)X(k+1) 0..2 arrays with no 2X2 subblock having equal diagonal elements or equal antidiagonal elements, and new values 0..2 introduced in row major order.at n=29A203984
- T(n,k)=Number of (n+1)X(k+1) 0..2 arrays with no 2X2 subblock having equal diagonal elements or equal antidiagonal elements, and new values 0..2 introduced in row major order.at n=34A203984
- Number of (n+1)X7 0..2 arrays with column and row pair sums b(i,j)=a(i,j)+a(i,j-1) and c(i,j)=a(i,j)+a(i-1,j) such that b(i,j)*b(i-1,j)-c(i,j)*c(i,j-1) is nonzero.at n=1A204104
- T(n,k)=Number of (n+1)X(k+1) 0..2 arrays with column and row pair sums b(i,j)=a(i,j)+a(i,j-1) and c(i,j)=a(i,j)+a(i-1,j) such that b(i,j)*b(i-1,j)-c(i,j)*c(i,j-1) is nonzero.at n=26A204106
- T(n,k)=Number of (n+1)X(k+1) 0..2 arrays with column and row pair sums b(i,j)=a(i,j)+a(i,j-1) and c(i,j)=a(i,j)+a(i-1,j) such that b(i,j)*b(i-1,j)-c(i,j)*c(i,j-1) is nonzero.at n=22A204106
- Floor(m^n/n) with n >= m >= 1.at n=41A246003