11013191domain: NAppears in sequencesa(n) = numerator of b(n), where b(1)=1, b(n+1) = sum{k|n} 1/b(k).at n=12A127939a(n) = denominator of b(n), where b(1)=1, b(n+1) = sum{k|n} 1/b(k).at n=13A127940